问 实在不理解下面这段代码是如何运作的，那位高手给指点一下撒
小弟先谢了
void Delay(int time)
// time=0: adjust the Delay function by WatchDog timer.//
// time>0: the number of loop time//
// 100us resolution.//
{
    int i,adjust=0;
    if(time==0)
    {
        time=200;
        adjust=1;
        delayLoopCount=400;
        rWTCON=((MCLK/1000000-1)<<8)|(2<<3);    // 1M/64,Watch-dog,nRESET,interrupt disable//
        rWTDAT=0xffff;
        rWTCNT=0xffff;     
        rWTCON=((MCLK/1000000-1)<<8)|(2<<3)|(1<<5); // 1M/64,Watch-dog enable,nRESET,interrupt disable //
    }
    for(;time>0;time--)
        for(i=0;i<delayLoopCount;i++);
    if(adjust==1)
    {
        rWTCON=((MCLK/1000000-1)<<8)|(2<<3);
        i=0xffff-rWTCNT;   //  1count/16us?????????//
        delayLoopCount=8000000/(i*64);    //400*100/(i*64/200)   //
    }
} 答 1: 对着注释讲得很清楚啦延时100us,如Delay(1)为延时100us,Delay(10)为延时1000us...
Delay(0)进行校准，使在各种工作时钟下都能满足延时100us的基准 答 2: 十分感谢阿南我已明白，十分感谢拉