EEPW论坛

问     下午用keil C51写的外部中断1函数，该函数是用于作为读取外部键盘值的。当有按键按下时硬件产生中断，然后延时一定时间去抖动，再读取按键值。当延时去抖动用外部延时子程序时，每次按下按键都会产生死机现象。当延时去抖动不调用外部子程序，而作了个for语句则不会产生死机现象。

      答 1: 不介意的话 程序发上来看看 答 2: 死机时的程序void Key_Int(void) interrupt 2 using 1
{
    unsigned char data i,SendCmd[4]={0x1B,0x2A,0x00,0x1B};
    unsigned char data Key_Val;
    unsigned int delaytime;
    for (delaytime = 0; delaytime < 0x3ff; delaytime++);//键盘去抖动
    Key = 1;
    if (!Key)
    {
        Key_Val = KeyComd[P4 & 0x0f];
        switch (Key_Val)
        {
            case 1:
                    SendCmd[0] = 0xff;                //发送键盘命令值
                    SendCmd[1] = 0x00;
                    break;
            case 2:
                    SendCmd[0] = 0xfe;
                    SendCmd[1] = 0x01;
                    break;
            case 3:
                    SendCmd[0] = 0xfd;
                    SendCmd[1] = 0x02;
                    break;
            case 4:
                    SendCmd[0] = 0xfb;
                    SendCmd[1] = 0x04;
                    break;
            case 5:
                    SendCmd[0] = 0xfa;
                    SendCmd[1] = 0x05;
                    break;
            case 6:
                    SendCmd[0] = 0xf9;
                    SendCmd[1] = 0x06;
                    break;
            case 7:
                    SendCmd[0] = 0xf7;
                    SendCmd[1] = 0x08;
                    break;
            case 8:
                    SendCmd[0] = 0xf6;
                    SendCmd[1] = 0x09;
                    break;
            case 9:
                    SendCmd[0] = 0xf5;
                    SendCmd[1] = 0x0a;
                    break;
            case 10:
                    SendCmd[0] = 0xf3;
                    SendCmd[1] = 0x0c;
                    break;
            case 11:
                    SendCmd[0] = 0xf2;
                    SendCmd[1] = 0x0d;
                    break;
            case 12:
                    SendCmd[0] = 0xf1;
                    SendCmd[1] = 0x0E;
                    break;
            case 13:
                    SendCmd[0] = 0xef;
                    SendCmd[1] = 0x10;
            case 14:
                    SendCmd[0] = 0xee;
                    SendCmd[1] = 0x11;
                    break;
            case 15:
                    SendCmd[0] = 0xed;
                    SendCmd[1] = 0x12;
                    break;
            default:break;
        }
        SendCmd[2] = 0xff;
        SendCmd[3] = 0x00;
        for (i = 0; i < 4; i++)            //串口发送
        {
            ACC = SendCmd[i];
            TB8 = P;
            SBUF = SendCmd[i];
            err = 0;
            while (!TI)
            {
                err++;
                if (err > 5000)
                {
                    break;
                }            
            }
            TI = 0;
        }
    }
} 答 3: 对不起，发错了！上面是没有死机时的程序如果将   for (delaytime = 0; delaytime < 0x3ff; delaytime++);
改成     Delay(10);//延时10ms
就产生死机现象
答 4: 检查是不是内存不足，导致堆栈溢出了？    你的延时函数是否在其它地方还有调用？如果有的话，要声明成可重入的。 答 5: 函数重入问题，需要重入声明。不过我不推荐在中断中调用函数 答 6: 编译的时候有没有提示L15警告 答 7: 不要在中断中处理那么多程序。可以改成标志 答 8: 请注意delaytime的数据类型！ 答 9: to gwnpeter,编译时没有任何警告 答 10: to lxb_gd ，delaytime是unsigned int

我也遇到这种问题，在串口中断中调用一个显示函数，可是一点反应都没有，现在还不知到怎么解决这个问题呢，郁闷……

中断函数调用死延时会出现以外的结果！

中断中加的东西太多的话 会死的

请问楼主后来怎么解决的呢？我也遇到这样的问题了。我在想可不可以把键扫放在中断以外的地方，可是不知道怎样实现。