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问 F449和F148自带的两个硬件异步串口都被占用了，
两个芯片之间需要数据交换，只能通过软串口实现，
是不是通过timerA或timerB的定时捕获方式来实现呢，
请教具体的实现方法，谢谢。 答 1: //******************************************************************************
// MSP-FET430X110 Demo - Timer_A UART Ultra-low Power 2400 Echo, 32kHz ACLK
//
// Description: Use timer_A CCR0 hardware output modes and SCCI data latch to
// to implement UART function 2400 baud. Software does not directly read and
// write to RX and TX pins, instead proper use of output modes and SCCI data
// latch are demonstrated. Use of these hardware features eliminates ISR
// latency effects as hardware insures that output and input bit latching and
// timing are perfectly synchronised with timer_A regardless of other
// software activity. In the Mainloop the UART function readies the UART to
// receive one character and waits in LPM3 with all activity interrupt driven.
// After a character has been received, the UART receive function forces exit
// from LPM3 in the Mainloop which echo's back the received character.
// ACLK = TACLK = LFXT1 = 32768, MCLK = SMCLK = DCO ~ 800k
// //*An external watch crystal is required on XIN XOUT for ACLK*//
//
// MSP430F1121
// -----------------
// /|\| XIN|-
// | | | 32kHz
// --|RST XOUT|-
// | |
// | CCI0A/TXD/P1.1|-------->
// | | 2400 8N1
// | CCI0B/RXD/P2.2|<--------
//
#define RXD 0x04 // RXD on P2.2
#define TXD 0x02 // TXD on P1.1

// Conditions for 2400 Baud SW UART, ACLK = 32768

#define Bitime_5 0x06 // ~ 0.5 bit length + small adjustment
#define Bitime 0x0E // 427us bit length ~ 2341 baud

unsigned int RXTXData;
unsigned char BitCnt;

void TX_Byte (void);
void RX_Ready (void);

// M.Buccini
// Texas Instruments, Inc
// September 2003
// Built with IAR Embedded Workbench Version: 1.26B
// January 2004
// Updated for IAR Embedded Workbench Version: 2.21B
//******************************************************************************


#include <MSP430x11x1.h>

void main (void)
{
WDTCTL = WDTPW + WDTHOLD; // Stop watchdog timer
CCTL0 = OUT; // TXD Idle as Mark
TACTL = TASSEL_1 + MC_2; // ACLK, continuous mode
P1SEL = TXD; // P1.1/TA0 for TXD function
P1DIR = TXD; // TXD output on P1
P2SEL = RXD; // P2.2/TA0 as RXD input

// Mainloop
for (;;)
{
RX_Ready(); // UART ready to RX one Byte
_BIS_SR(LPM3_bits + GIE); // Enter LPM3 w/ interr until char RXed
TX_Byte(); // TX Back RXed Byte Received
}
}


// Function Transmits Character from RXTXData Buffer
void TX_Byte (void)
{
BitCnt = 0xA; // Load Bit counter, 8data + ST/SP
while (CCR0 != TAR) // Prevent async capture
CCR0 = TAR; // Current state of TA counter
CCR0 += Bitime; // Some time till first bit
RXTXData |= 0x100; // Add mark stop bit to RXTXData
RXTXData = RXTXData << 1; // Add space start bit
CCTL0 = OUTMOD0 + CCIE; // TXD = mark = idle
while ( CCTL0 & CCIE ); // Wait for TX completion
}


// Function Readies UART to Receive Character into RXTXData Buffer
void RX_Ready (void)
{
BitCnt = 0x8; // Load Bit counter
CCTL0 = SCS + CCIS0 + OUTMOD0 + CM1 + CAP + CCIE; // Sync, Neg Edge, Cap
}


// Timer A0 interrupt service routine
#pragma vector=TIMERA0_VECTOR
__interrupt void Timer_A (void)
{
CCR0 += Bitime; // Add Offset to CCR0

// RX
if (CCTL0 & CCIS0) // RX on CCI0B?
{
if( CCTL0 & CAP ) // Capture mode = start bit edge
{
CCTL0 &= ~ CAP; // Switch from capture to compare mode
CCR0 += Bitime_5;
}
else
{
RXTXData = RXTXData >> 1;
if (CCTL0 & SCCI) // Get bit waiting in receive latch
RXTXData |= 0x80;
BitCnt --; // All bits RXed?
if ( BitCnt == 0)
//>>>>>>>>>> Decode of Received Byte Here <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
{
CCTL0 &= ~ CCIE; // All bits RXed, disable interrupt
_BIC_SR_IRQ(LPM3_bits); // Clear LPM3 bits from 0(SR)
}
//>>>>>>>>>> Decode of Received Byte Here <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
}
}
// TX
else
{
if ( BitCnt == 0)
CCTL0 &= ~ CCIE; // All bits TXed, disable interrupt
else
{
CCTL0 |= OUTMOD2; // TX Space
if (RXTXData & 0x01)
CCTL0 &= ~ OUTMOD2; // TX Mark
RXTXData = RXTXData >> 1;
BitCnt --;
}
}
} 答 2: 多谢版主，
还有一个问题请教，
如果我使用F148的一个硬串口，和F449的一个模拟软串口，
采用2400的bps，应该也是可以通讯，对吗？ 答 3: 请问版主，430的硬件串口是全双工还是半双工？软件串口是半双工吗？ 答 4: 硬件串口是全双工,软件串口是半双工 答 5: 终于得到证实了，谢谢版主