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静态数码管显示,通过按键控制数码管的数值变化.
视频我贴在优酷了,下面是视频的链接
http://v.youku.com/v_show/id_XNDU2MzI1NjQw.html
时钟输入是接在key1上,下面是代码

library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;

entity scanseg is
port(clk : in std_logic;
 segctl : out std_logic_vector(7 downto 0);
 segout : out std_logic_vector(6 downto 0));
end scanseg;

architecture behave of scanseg is
 signal databuf : std_logic_vector(3 downto 0);
begin
segctl<="00000000";

process(clk)
begin
 if clk'event and clk = '1' then
 databuf<=databuf+"0001";
 end if;
end process;

process(databuf)
begin
 case databuf is
 when "0000" =>
  segout <= "0000001"; --显示0
 when "0001" =>
  segout <= "1111001"; --显示1
 when "0010" =>
  segout <= "0010010"; --显示2
 when "0011" =>
  segout <= "0000110"; --显示3
 when "0100" =>
  segout <= "1001100"; --显示4
 when "0101" =>
  segout <= "0100100"; --显示5
 when "0110" =>
  segout <= "0100000"; --显示6
 when "0111" =>
  segout <= "0001111"; --显示7
 when "1000" =>
  segout <= "0000000"; --显示8
 when "1001" =>
  segout <= "0000100"; --显示9
 when "1010" =>
  segout <= "0001000"; --显示A
 when "1011" =>
  segout <= "1100000"; --显示b
 when "1100" =>
  segout <= "0110001"; --显示C
 when "1101" =>
  segout <= "1000010"; --显示d
 when "1110" =>
  segout <= "0110000"; --显示E
 when "1111" =>
  segout <= "0111000"; --显示F
 when others =>
  segout <= "0000000";
 end case;
end process;
end behave;

我写了好几个程序，用按键控制会变化，但将触发信号接到时钟管脚上并就静止不变化，我想真的是晶振没有焊接好

动态数码管显示，将Y2的50M频率经分频后动态扫描数码管显示。
注意：如果不进行分频的话，由于频率太高，数码管将不会显示任何数字。



下面是给出了分频器和动态扫描代码及SOF文件：（晶振使用Y2）
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