问 如下代码，请大家看看有什么不妥？调试时，加载所有程序（25K,ARM2132),
UART1执行一次后，就不再进入中断，真是郁闷
        
         //TIME0中断设置
         T0TC   = 0;                    
    T0PR   = 0;            
    T0MCR  = 0x03;         
    T0MR0  = Fpclk / 1;
    T0TCR  = 0x01;            
       VICIntSelect = 0x00;        
    VICVectCntl2 = 0x20 | 0x04;                VICVectAddr2 = (uint32)IRQ_Timer0;    
    VICIntEnable = 1 << 0x04;
         //UART0设置
         U0LCR = 0x83;
    Fdiv = (Fpclk / 16) / SIM100_BAUD;
    U0DLM = Fdiv / 256;
    U0DLL = Fdiv % 256;
    U0LCR = 0x03;    
         U0FCR = 0x01;                    
        U0IER = 0x01;                        VICVectCntl0 = 0x20 | 0x06;        
         VICVectAddr0 = (uint32)IRQ_UART0;    
         VICIntEnable = 1 << 0x06;

         //uart1 中断设置
    set.datab  = 8;
    set.stopb  = 1;
    set.parity = 0;    
    U1LCR = 0X83;
    Fdiv = (Fpclk / 16) / GPS_BAUD;
    U1DLM = Fdiv / 256;
    U1DLL = Fdiv % 256;
    U1LCR = 0x03;
        
    U1FCR = 0x01;                        U1IER = 0x00;                        VICVectCntl1 = 0x20 | 0x07;        
    VICVectAddr1 = (uint32)IRQ_UART1;    
    VICIntEnable = 1 << 0x07;                
    IRQEnable();                         答 1: xx IRQEnable(); 放在U1LCR = 0X83;前试试。
//TIME0中断设置
//UART0设置
有没有使能IRQ中断？程序不全，别人不好理解，就更不好谈程序妥不妥了。

答 2: 换个方式试一下VICIntEnable = 1 << 0x04;
VICIntEnable = 1 << 0x06;
VICIntEnable = 1 << 0x07;
改为
VICIntEnable |= （1 << 0x04）|（1 << 0x06）|（1 << 0x07）;